(2x+5)(2x^2-5x+3)=0

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Solution for (2x+5)(2x^2-5x+3)=0 equation: 


Simplifying
(2x + 5)(2x2 + -5x + 3) = 0

Reorder the terms:
(5 + 2x)(2x2 + -5x + 3) = 0

Reorder the terms:
(5 + 2x)(3 + -5x + 2x2) = 0

Multiply (5 + 2x) * (3 + -5x + 2x2)
(5(3 + -5x + 2x2) + 2x * (3 + -5x + 2x2)) = 0
((3 * 5 + -5x * 5 + 2x2 * 5) + 2x * (3 + -5x + 2x2)) = 0
((15 + -25x + 10x2) + 2x * (3 + -5x + 2x2)) = 0
(15 + -25x + 10x2 + (3 * 2x + -5x * 2x + 2x2 * 2x)) = 0
(15 + -25x + 10x2 + (6x + -10x2 + 4x3)) = 0

Reorder the terms:
(15 + -25x + 6x + 10x2 + -10x2 + 4x3) = 0

Combine like terms: -25x + 6x = -19x
(15 + -19x + 10x2 + -10x2 + 4x3) = 0

Combine like terms: 10x2 + -10x2 = 0
(15 + -19x + 0 + 4x3) = 0
(15 + -19x + 4x3) = 0

Solving
15 + -19x + 4x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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